初三数学计算题

www.zhiqu.org     时间: 2024-06-01
(30-4x)(20-6x)=450
600-180x-80x+24x²-450=0
24x²-260x+150=0
12x²-130x+75=0
x²-(130/12)x+75/12=0
x²-(65/6)x+(65/12)²-(65/12)²+75/12=0
(x-65/12)²=(65/12)²-75/12=3325/144
x-65/12=±根号下(3325/144)=±5/12根号下133
x1=(5根号下133+65)/12
x2=(65-5根号下133)/12

原方程即600+24x²-260x=450,
24x²-260x+150=0
12x²-130x+75=0
△=16900-4×12×75=13300
x1=(130+10√133)/24=(65+5√133)/12
x2=(65-5√133)/12
希望对你有帮助。

解:600-180X-80X+24X2=450
600-260X+24X2=450
24X2-260X+150=0
12X2-130X+75=0
利用公式法 求出X
X=(65+5根号133)/12 x=(65-5根号133)/12

30×20-4x×20-30×6x+24x的平方=450
600-80x-180x+24x方=450
600-260x+24x方-450=0
24x方-260x+150=0
24x²-260x+150=0
12x²-130x+75=0
△130²-4×12×75=13300
x=(130±√13300)/24
=(130±10√133)/24
=(65±5√133)/12

给我三分钟



初三数学计算题~

①5√8-2√32+√50
=5*3√2-2*4√2+5√2
=√2(15-8+5)
=12√2
②√6-√3/2-√2/3
=√6-√6/2-√6/3
=√6/6
③(√45+√27)-(√4/3+√125)
=(3√5+3√3)-(2√3/3+5√5)
=-2√5+7√5/3
④(√4a-√50b)-2(√b/2+√9a)
=(2√a-5√2b)-2(√2b/2+3√a)
=-4√a-6√2b
⑤√4x*(√3x/2-√x/6)
=2√x(√6x/2-√6x/6)
=2√x*(√6x/3)
=2/3*|x|*√6
⑥(x√y-y√x)÷√xy
=x√y÷√xy-y√x÷√xy
=√x-√y
⑦(3√7+2√3)(2√3-3√7)
=(2√3)^2-(3√7)^2
=12-63
=-51
⑧(√32-3√3)(4√2+√27)
=(4√2-3√3)(4√2+3√3)
=(4√2)^2-(3√3)^2
=32-27
=5
⑨(3√6-√4)?
=(3√6)^2-2*3√6*√4+(√4)^2
=54-12√6+4
=58-12√6
⑩(1+√2-√3)(1-√2+√3)
=[1+(√2-√3)][1-(√2-√3)]
=1-(√2-√3)^2
=1-(2+3+2√6)
=-4-2√6

(1)5√12×√18
=5*2√3*3√2
=30√6;

(2)-6√45×(-4√48)
=6*3√5*4*4√3
=288√15;

(3)√(12a)×√(3a) /4
=√(36a^2)/4
=6a/4
=3a/2.
5.
x^2(y+z)^2-2xy(x-z)(y+z)+y^2(x-z)^2
=[x(y+z)-y(x-z)]^2
=(xz+yz)^2
=z^2(x+y)^2

6.
3(a+2)^2+28(a+2)-20
=[3(a+2)-2][(a+2)+10]
=(3a+4)(a+12)

7.
(a+b)^2-(b-c)^2+a^2-c^2
=(a+b)^2-c^2+a^2-(b-c)^2
=(a+b+c)(a+b-c)+(a+b-c)(a-b+c)
=(a+b-c)(a+b+c+a-b+c)
=2(a+b-c)(a+c)

8.
x(x+1)(x^2+x-1)-2
=(x^2+x)(x^2+x-1)-2
=(x^2+x)^2-(x^2+x)-2
=(x^2+x-2)(x^2+x+1)
=(x+2)(x-1)(x^2+x+1)

9.
9x^2(x-1)^2-3(x^2-x)-56
=9x^2(x-1)^2-3x(x-1)-56
=[3x(x-1)-8][3x(x-1)+7]
=(3x^2-3x-8)(3x^2-3x+7)
有理数练习
练习一(B级)
(一)计算题:
(1)23+(-73) (2)(-84)+(-49) (3)7+(-2.04) (4)4.23+(-7.57) (5)(-7/3)+(-7/6) (6)9/4+(-3/2) (7)3.75+(2.25)+5/4 (8)-3.75+(+5/4)+(-1.5)
5.
x^2(y+z)^2-2xy(x-z)(y+z)+y^2(x-z)^2
=[x(y+z)-y(x-z)]^2
=(xz+yz)^2

=z^2(x+y)^2

6.
3(a+2)^2+28(a+2)-20
=[3(a+2)-2][(a+2)+10]
=(3a+4)(a+12)

7.
(a+b)^2-(b-c)^2+a^2-c^2
=(a+b)^2-c^2+a^2-(b-c)^2
=(a+b+c)(a+b-c)+(a+b-c)(a-b+c)
=(a+b-c)(a+b+c+a-b+c)
=2(a+b-c)(a+c)

8.
x(x+1)(x^2+x-1)-2
=(x^2+x)(x^2+x-1)-2
=(x^2+x)^2-(x^2+x)-2
=(x^2+x-2)(x^2+x+1)
=(x+2)(x-1)(x^2+x+1)

9.
9x^2(x-1)^2-3(x^2-x)-56
=9x^2(x-1)^2-3x(x-1)-56
=[3x(x-1)-8][3x(x-1)+7]
=(3x^2-3x-8)(3x^2-3x+7)
望采纳~~

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